PTHH:

`C+2H_2`$\xrightarrow[]{t^o}$`CH_4`

`X:CH_4`

`2CH_4`$\xrightarrow[]{t^o}$`C_2H_2+3H_2`

`Y:C_2H_2`

`C_2H_2+Br_2->C_2H_2Br_2`

`C_2H_2+2Br_2->C_2H_2Br_4`

`C_2H_2+H_2`$\xrightarrow[Pb,PbCO_3]{t^o}$`C_2H_4`

`Z:C_2H_4`

`3C_2H_2`$\xrightarrow[C]{600^oC}$`C_6H_6`

`D:C_6H_6`

`nC_2H_4`$\xrightarrow[]{t^o,p,xt}$$(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n$

`E:`$(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n$

`C_2H_4+H_2O`$\xrightarrow[]{H+,t^o}$`C_2H_5OH`

`F:dd` `C_2H_5OH`

Giải thích các bước giải:

$X:CH_4\\Y:C_2H_2\\Z:C_2H_4\\D:C_6H_6\\E:(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n\\F:C_2H_5OH$

Các phản ứng xảy ra:

$C+2H_2\xrightarrow{t^o}CH_4$

$2CH_4\xrightarrow{t^o}C_2H_2+3H_2$

$C_2H_2+H_2\xrightarrow{Pd/PbCO_3,\ t^o}C_2H_4$

$3C_2H_2\xrightarrow{\rm bột\ C,\ 600^oC}C_6H_6$

$nC_2H_4\xrightarrow{xt,\ t^o,\ P}(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n$

$C_2H_4+H_2O\xrightarrow{H^+,\ t^o}C_2H_5OH$