Đáp án:

\(\begin{array}{l}
\% C{H_4} = 22,86\% \\
\% {C_2}{H_4} = 40\% \\
\% {C_2}{H_2} = 37,14\% 
\end{array}\)

Giải thích các bước giải:

\(\begin{array}{l}
a)\\
{C_2}{H_4} + B{r_2} \to {C_2}{H_4}B{r_2}\\
{C_2}{H_2} + 2B{r_2} \to {C_2}{H_2}B{r_4}\\
{C_2}{H_2} + 2AgN{O_3} + 3N{H_3} \to A{g_2}{C_2} + 2N{H_4}N{O_3}\\
b)\\
{n_{hh}} = \dfrac{{6,72}}{{22,4}} = 0,3mol\\
{n_{C{H_4}}} = \dfrac{{2,24}}{{22,4}} = 0,1mol\\
{n_{A{g_2}{C_2}}} = \dfrac{{24}}{{240}} = 0,1mol\\
{n_{{C_2}{H_2}}} = {n_{A{g_2}{C_2}}} = 0,1mol\\
{n_{{C_2}{H_4}}} = 0,3 - 0,1 - 0,1 = 0,1mol\\
{m_{C{H_4}}} = 0,1 \times 16 = 1,6g\\
{m_{{C_2}{H_4}}} = 0,1 \times 28 = 2,8g\\
{m_{{C_2}{H_2}}} = 0,1 \times 26 = 2,6g\\
\% C{H_4} = \dfrac{{1,6}}{{1,6 + 2,8 + 2,6}} \times 100\%  = 22,86\% \\
\% {C_2}{H_4} = \dfrac{{2,8}}{{1,6 + 2,8 + 2,6}} \times 100\%  = 40\% \\
\% {C_2}{H_2} = 100 - 22,86 - 40 = 37,14\% 
\end{array}\)