Đáp án:

Bạn tham khảo lời giải ở dưới nhé!!!

Giải thích các bước giải:

\(\begin{array}{l}
1,CuC{l_2} + 2K{\rm{O}}H \to Cu{(OH)_2} + 2KCl\\
2,F{\rm{e}}{(OH)_2} + 2HCl \to F{\rm{e}}C{l_2} + 2{H_2}O\\
3,F{\rm{e}}{(OH)_2} + {H_2}S{O_4} \to F{\rm{e}}S{O_4} + 2{H_2}O\\
4,ZnO + 2HCl \to ZnC{l_2} + {H_2}O\\
5,F{e_2}{O_3} + 3{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + 3{H_2}O\\
6,Cu{(N{O_3})_2} + 2NaOH \to Cu{(OH)_2} + 2NaN{O_3}\\
7,2{N_2} + 5{O_2} \to 2{N_2}{O_5}\\
8,{N_2} + {O_2} \to 2NO\\
9,2NO + {O_2} \to 2N{O_2}\\
10,4P + 5{O_2} \to 2{P_2}{O_5}\\
11,2S{O_2} + {O_2} \to 2S{O_3}\\
12,{N_2}{O_5} + {H_2}O \to 2HN{O_3}\\
13,CuS{O_4} + Ba{(N{O_3})_2} \to Cu{(N{O_3})_2} + BaS{O_4}\\
14,F{e_2}{(S{O_4})_3} + 6NaOH \to 2Fe{(OH)_3} + 3N{a_2}S{O_4}\\
15,CaO + C{O_2} \to CaC{O_3}\\
16,BaO + {H_2}O \to Ba{(OH)_2}\\
17,BaC{O_3} + C{O_2} + {H_2}O \to Ba{(HC{O_3})_2}\\
18,2Na + {H_3}P{O_4} \to N{a_2}HP{O_4} + {H_2}\\
19,6Na + 2{H_3}P{O_4} \to 2N{a_3}P{O_4} + 3{H_2}\\
20,2Na + 2{H_3}P{O_4} \to 2Na{H_2}P{O_4} + {H_2}\\
21,2KN{O_3} \to 2KN{O_2} + {O_2}\\
22,Ba{(N{O_3})_2} + {H_2}S{O_4} \to BaS{O_4} + 2HN{O_3}\\
23,Ba{(N{O_3})_2} + N{a_2}S{O_4} \to BaS{O_4} + 2NaN{O_3}\\
24,AlC{l_3} + 3NaOH \to Al{(OH)_3} + 3NaCl\\
25,Al{(OH)_3} + NaOH \to NaAl{O_2} + 2{H_2}O\\
26,2KCl{O_3} \to 2KCl + 3{O_2}\\
27,Fe{(N{O_3})_3} + 3KOH \to Fe{(OH)_3} + 3KN{O_3}\\
28,{H_2}S{O_4} + N{a_2}C{O_3} \to N{a_2}S{O_4} + C{O_2} + {H_2}O\\
29,2HCl + CaC{O_3} \to CaC{l_2} + C{O_2} + {H_2}O\\
30,Ba{(OH)_2} + 2HCl \to BaC{l_2} + 2{H_2}O\\
31,5S{O_2} + 2KMn{O_4} + 2{H_2}O \to 2MnS{O_4} + {K_2}S{O_4} + 2{H_2}S{O_4}\\
32,{H_2}S + 2FeC{l_3} \to 2FeC{l_2} + 2HCl + S\\
33,3{H_2}S + 2KMn{O_4} \to 2Mn{O_2} + 2KOH + 2{H_2}O + 3S\\
34,{H_2}S + CuS{O_4} \to CuS + {H_2}S{O_4}\\
35,3{H_2}S + {H_2}S{O_4} \to 4S + 4{H_2}O\\
36,2{H_2}S + 3{O_2} \to 2S{O_2} + 2{H_2}O\\
37,4C{l_2} + 4{H_2}O + {H_2}S \to {H_2}S{O_4} + 8HCl\\
38,{K_2}C{r_2}{O_7} + 14HCl \to 2KCl + 2CrC{l_3} + 3C{l_2} + 7{H_2}O
\end{array}\)

$@Heley$

$1) CuCl_{2} + 2KOH → Cu(OH)_{2} + 2KCl$

$2) Fe(OH)_{2} + 2HCl → FeCl_{2} + 2H_{2}O$

$3) Fe(OH)_{2} + H_{2}SO_{4} → FeSO_{4} + 2H_{2}O$

$4) ZnO + 2HCl → ZnCl_{2} + H_{2}O$

$5) Fe_{2}O_{3} + 3H_{2}SO_{4} → Fe_{2}(SO_{4})_{3} + 3H_{2}O$

$6) Cu(NO_{3})_{2} + 2NaOH → Cu(OH)_{2} + 2NaNO_{3}$

$7) 4N + 5O_{2} → 2N_{2}O_{5}$

$8) N_{2} + O_{2} → 2NO$

$9) 2NO + O_{2} → 2NO_{2}$

$10) 4P + 5O_{2} → 2P_{2}O_{5}$

$11) 2SO_{2} + O_{2} → 2SO_{3}$

$12) N_{2}O_{5} + H_{2}O → 2HNO_{3}$

$13) CuSO_{4} + Ba(NO_{3})_{2}→ Cu(NO_{3})_{2} + BaSO_{4}$

$14) Fe_{2}(SO_{4})_{3} + 6NaOH → 2Fe(OH)_{3} + 3Na_{2}SO_{4}$

$15) CaO + CO_{2} → CaCO_{3}$

$16) BaO + H_{2}O → Ba(OH)_{2}$

$17) BaCO_{3} + H_{2}O + CO_{2} → Ba(HCO_{3})_{2}$

$18) 2Na + H_{3}PO_{4} → Na_{2}HPO_{4} + H_{2}$

$19) 6Na + 2H_{3}PO_{4} → 2Na_{3}PO_{4} + 3H_{2}$

$20) 2Na + 2H_{3}PO_{4} → 2NaH_{2}PO_{4} + H_{2}$

$21) 2KNO_{3} → 2KNO_{2} + O_{2}$

$22) Ba(NO_{3})_{2} + H_{2}SO_{4} → BaSO_{4} + 2HNO_{3}$

$23) Ba(NO_{3})_{2} + Na_{2}SO_{4} → BaSO_{4} + 2NaNO_{3}$

$24) AlCl_{3} + 3NaOH → Al(OH)_{3} + 3NaCl$

$25) Al(OH)_{3} + NaOH → NaAlO_{2} + 2H_{2}O$

$26) 2KClO_{3} → 2KCl + 3O_{2}$

$27) Fe(NO_{3})_{3} + 3KOH → Fe(OH)_{3} + 3KNO_{3}$

$28) H_{2}SO_{4} + Na_{2}CO_{3} → Na_{2}SO_{4} + H_{2}O + CO_{2}↑$

$29) 2HCl + CaCO_{3} → CaCl_{2} + H_{2}O + CO_{2}$

$30) Ba(OH)_{2} + 2HCl → BaCl_{2} + 2H_{2}O$

$31) 5SO_{2}+ 2KMnO_{4} + 2H_{2}O → 2MnSO_{4} + K_{2}SO_{4} + 2H_{2}SO_{4}$

$32) H_{2}S + 2FeCl_{3} → S + 2FeCl_{2} + 2HCl$

$33) 3H_{2}S + 2KMnO_{4}→ 2KOH + 2MnO_{2}+ 3S + 2H_{2}O$

$34) H_{2}S + CuSO_{4}→ CuS + H_{2}SO_{4}$

$35) H_{2}S + H_{2}SO_{4} → SO_{2} + 2H_{2}O + S$

$36) 2H_{2}S + 3O_{2} → 2SO_{2}+ 2H_{2}O$

$37) H_{2}S + 4Cl_{2} + 4H_{2}O → H_{2}SO_{4} + 8HCl$

$38) K_{2}Cr_{2}O_{7} + 14HCl → 2CrCl_{3} + 2KCl + 3Cl_{2}+ 7H_{2}O$

#$BTS$