Em tham khảo nha:

\(\begin{array}{l}
(1)4Al + 3C \xrightarrow{t^0} A{l_4}{C_3}\\
(2)\,2Al + 3S \xrightarrow{t^0} A{l_2}{S_3}\\
(3)\,2Al + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}\\
(4)2\,Al + 6HN{O_3} \to 2Al{(N{O_3})_3} + 3{H_2}\\
(5)\,2A{l_2}{O_3} \xrightarrow{\text{ điện phân nóng chảy} } 4Al + 3{O_2}\\
(6)\,4Al + 3{O_2} \xrightarrow{t^0} 2A{l_2}{O_3}\\
(7)\,2Al + 2NaOH + 2{H_2}O \to 2NaAl{O_2} + 3{H_2}\\
(8)\,2Al + 6HCl \to 2AlC{l_3} + 3{H_2}\\
(9)\,A{l_4}{C_3} + 12{H_2}O \to 3C{H_4} + 4Al{(OH)_3}\\
(10)\,A{l_2}{S_3} + 6{H_2}O \to 2Al{(OH)_3} + 3{H_2}S\\
(11)\,A{l_2}{(S{O_4})_3} + 6NaOH \to 2Al{(OH)_3} + 3N{a_2}S{O_4}\\
(12)\,2Al{(OH)_3} + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 6{H_2}O\\
(13)\,Al{(N{O_3})_3} + 3NaOH \to Al{(OH)_3} + 3NaN{O_3}\\
(14)\,Al{(OH)_3} + 3HN{O_3} \to Al{(N{O_3})_3} + 3{H_2}O\\
(15)\,2Al{(OH)_3} \xrightarrow{t^0} A{l_2}{O_3} + 3{H_2}O\\
(16)\,Al{(OH)_3} + NaOH \to NaAl{O_2} + 2{H_2}O\\
(17)\,2NaAl{O_2} + C{O_2} + 3{H_2}O \to N{a_2}C{O_3} + 2Al{(OH)_3}\\
(18)\,Al{(OH)_3} + 3HCl \to AlC{l_3} + 3{H_2}O\\
(19)\,AlC{l_3} + 3NaOH \to Al{(OH)_3} + 3NaCl\\
(20)\,2NaAl{O_2} + 4{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + N{a_2}S{O_4} + 4{H_2}O\\
(21)\,A{l_2}{(S{O_4})_3} + 8NaOH \to 2NaAl{O_2} + 3N{a_2}S{O_4} + 4{H_2}O\\
(22)\,A{l_2}{(S{O_4})_3} + 3BaC{l_2} \to 2AlC{l_3} + 3BaS{O_4}\\
(23)\,A{l_2}{S_3} + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}S\\
(24)\,A{l_2}{(S{O_4})_3} + 3Ba{(N{O_3})_2} \to 2Al{(N{O_3})_2} + 3BaS{O_4}\\
(25)\,4Al{(N{O_3})_3} \to 2A{l_2}{O_3} + 12N{O_2} + 3{O_2}\\
(26)\,A{l_2}{O_3} + 6HN{O_3} \to 2Al{(N{O_3})_3} + 3{H_2}O\\
(27)\,A{l_2}{O_3} + 2NaOH \to 2NaAl{O_2} + {H_2}O\\
(28)\,NaAl{O_2} + 4HCl \to NaCl + AlC{l_3} + 2{H_2}O\\
(29)\,AlC{l_3} + 4NaOH \to NaAl{O_2} + 3NaCl + 2{H_2}O\\
(30)\,2Al{(OH)_3} \xrightarrow{t^0} A{l_2}{O_3} + 3{H_2}O\\
(31)\,A{l_2}{O_3} + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}O\\
(32)\,2A{l_2}{(S{O_4})_3} \to 2A{l_2}{O_3} + 6S{O_2} + 3{O_2}\\
(33)\,Ba{(OH)_2} + 2Al{(OH)_3} \to Ba{(Al{O_2})_2} + 4{H_2}O\\
(34)\,Ba{(Al{O_2})_2} + 2C{O_2} + 4{H_2}O \to 2Al{(OH)_3} + Ba{(HC{O_3})_2}\\
(35)\,2Al + Ba{(OH)_2} + 2{H_2}O \to Ba{(Al{O_2})_2} + 3{H_2}
\end{array}\)

Đáp án:

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