Giải thích các bước giải:

 a) MSC: 24

Ta có: $\frac{5}{6}$ = $\frac{20}{24}$ ; $\frac{1}{4}$ = $\frac{6}{24}$ 

b) MSC: 30

Ta có: $\frac{1}{6}$ = $\frac{5}{30}$ ; $\frac{4}{5}$ = $\frac{24}{30}$ 

c)MSC: 72

Ta có: $\frac{4}{9}$ = $\frac{32}{72}$ ; $\frac{5}{8}$ = $\frac{45}{72}$ 

d)MSC: 36

Ta có: $\frac{5}{9}$ = $\frac{20}{36}$ ; $\frac{7}{36}$ giữ nguyên

e) MSC: 49

Ta có: $\frac{11}{49}$ giữ nguyên ; $\frac{3}{7}$ = $\frac{21}{49}$ 

g) MSC: 100

Ta có: $\frac{47}{100}$ giữ nguyên ; $\frac{17}{25}$ = $\frac{68}{100}$ 

a) `5/6 = (5×2)/(6×2) = 10/12`

`1/4 = (1×3)/(4×3) = 3/12`

b) `1/6 = (1×5)/(6×5) = 5/30`

`4/5 = (4×6)/(5×6) = 24/30`

c) `4/9 = (4×8)/(9×8) = 32/72`

`5/8 = (5×9)/(8×9) = 45/72`

d) `5/9 = (5×4)/(9×4) = 20/36`

`7/36 = 7/36`

e) `11/49 = 11/49`

`3/7 = (3×7)/(7×7) = 21/49`

g) `47/100 = 47/100`

`17/25 = (17×4)/(25×4) = 68/100`