Đáp án:

 12/

Gọi công thức muối là RX(R là kim loại, X là halogen)

RX + AgNO3 --> AgX + RNO3

 nAgX=$\frac{14,35}{108+X}$ 

nRX=$\frac{4,25}{R+X}$ 

Ta có nRX=nAgX

<=>$\frac{4,25}{R+X}$ =$\frac{14,35}{108+X}$ 

<=>459+4,25X=14,35R+14,35X

<=>10,1X+14,35R=459

Thay lần lượt các halogen là Flo, Clo,Brom,Iot

X=19(Flo)=>R=18,6(Loại)

X=35,5(Clo)=>R=7(Liti)

X=80(Br)=>R=-174,5(loại)

X=127(iot)=>R=-411.85(Loại)

=>Muối là LiCl

a/2HCl $\buildrel{{đpdd}}\over\longrightarrow$ H2 + Cl2

3Cl2 + 2Fe $\buildrel{{t^o}}\over\longrightarrow$ 2FeCl3

FeCl3 + 3NaOH --> Fe(OH)3 + 3NaCl

2NaCl + H2OS4đ $\buildrel{{t^o}}\over\longrightarrow$ Na2SO4 + 2HCl

HCl + CuO --> CuCl2 + H2O

CuCl2 -->Ag???

b/

2KMnO4+16HCl đ $\buildrel{{t^o}}\over\longrightarrow$ 2MnCl2 + 2KCl + 5Cl2 + 8H2O

Cl2 + H2 $\buildrel{{t^o}}\over\longrightarrow$ 2HCl

6HCl + Fe2O3 $\buildrel{{t^o}}\over\longrightarrow$ 2FeCl3 + 3H2O

FeCl3 + 3AgNO3 --> 3AgCl + Fe(NO3)3

2AgCl $\buildrel{{t^o}}\over\longrightarrow$ 2Ag+ Cl2

Cl2 +2 NaBr --> 2NaCl + Br2

Br2 + 2NaI --> 2NaBr + I2

c/

2KMnO4+16HCl đ $\buildrel{{t^o}}\over\longrightarrow$ 2MnCl2 + 2KCl + 5Cl2 + 8H2O

Cl2 + H2 $\buildrel{{t^o}}\over\longrightarrow$ 2HCl

2HCl + Fe --> FeCl2 + H2

FeCl2 + 2AgNO3 --> 2AgCl + Fe(NO3)2

2AgCl $\buildrel{{t^o}}\over\longrightarrow$ 2Ag+ Cl2

d/

2HCl $\buildrel{{đpdd}}\over\longrightarrow$ H2 + Cl2

C3l2 + 2Fe $\buildrel{{t^o}}\over\longrightarrow$ 2FeCl3

FeCl3 + 3NaOH --> Fe(OH)3 + 3NaCl

2Fe(OH)3 + 3H2SO4 --> Fe2(SO4)3 +6H2O

e/

2HCl $\buildrel{{đpdd}}\over\longrightarrow$ H2 + Cl2

Cl2 + 2Na $\buildrel{{t^o}}\over\longrightarrow$ 2NaCl

2NaCl + H2SO4đ $\buildrel{{t^o}}\over\longrightarrow$ Na2SO4 + 2HCl

2HCl + CuO --> CuCl2 + H2O

CuCl2 + 2AgNO3 --> 2AgCl + Cu(NO3)2

2AgCl $\buildrel{{t^o}}\over\longrightarrow$ 2Ag+ Cl2

f/

MnO2 + 4HCl đ $\buildrel{{t^o}}\over\longrightarrow$ MnCl2 + Cl2 + 2HO

3Cl2 + 6KOHđ $\buildrel{{100^oC}}\over\longrightarrow$ KClO3 + 5KCl + 3H2O

KClO3 +3 HCl --> KCl + 3Cl2 + 3H2O

2KCl + H2SO4 đ $\buildrel{{t^o}}\over\longrightarrow$ K2SO4 + 2HCl

2HCl $\buildrel{{đpdd}}\over\longrightarrow$ H2 + Cl2

Cl2 + Ca(OH)2 --> CaOCl2 + H2O

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