Em tham khảo!

$\text{1) 2Na+Cl2$\xrightarrow{t^o}$2NaCl}$

Tỉ lệ: $\text{2:1:2}$

$\text{2) N2+3H2$\buildrel{{t^o}}\over\rightleftharpoons$2NH3}$

Tỉ lệ: $\text{1:3:2}$

$\text{3) 2KNO3$\xrightarrow{t^o}$2KNO2+O2}$

Tỉ lệ: $\text{2:2:1}$

$\text{4) 2Al+6HCl$\xrightarrow{t^o}$2AlCl3+3H2}$

Tỉ lệ: $\text{2:6:2:3}$

$\text{5) 3BaCl2+Al2(SO4)3$\rightarrow$2AlCl3+3BaSO4}$

Tỉ lệ: $\text{3:1:2:3}$

$\text{6) 2C4H10+13O2$\xrightarrow{t^o}$8CO2+10H2O}$

Tỉ lệ: $\text{2:13:8:10}$

$\text{7) xFe2O3+(3x-2y)CO$\xrightarrow{t^o}$2FexOy+(3x-2y)CO2}$

Tỉ lệ: $\text{x:(3x-2y):2:(3x-2y)}$

$\text{8) Cu+2H2SO4(đặc,nóng)$\xrightarrow{t^o}$CuSO4+2SO2+H2O}$

Tỉ lệ: $\text{1:2:1:2:1}$

1, 2Na + Cl2 -> 2NaCl

2, N2 + 3H2 -> 2NH3

3, 2KNO3 -> 2KNO2 + O2

4, 2Al + 6HCl -> 2AlCl3 + 3H2

5, 3BaCl2 + Al2(SO4)3 -> 2AlCl3 + 3BaSO4

6, 2C4H10 + 13O2 -> 8CO2 + 10H2O

7, xFe2O3 + yCO -> 2FexOy + yCO2

8, Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O