$Đáp$ $án$ $+$ $Giải$ $thích$ $các$ $bước$ $giải$ $:$

$4,$ 2Al + 3Cl₂ → 2AlCl₃

$5,$ Fe₃O₄ + 8HCl → 2FeCl₃ + FeCl₂ + 4H₂O

$6,$ Fe₃O₄ + 4H₂SO₄ → FeSO₄ + Fe₂(SO₄)₃ + 4H₂O

$7,$ Al₂O₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂O

$8,$ Na₂CO₃ + 2HCl → 2NaCl + CO₂+ H₂O

$9,$ 2Al(OH)₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

$10,$ 3Ba(OH)₂ + Fe₂(SO₄)₃ → 2Fe(OH)₃ + 3BaSO₄

$11,$ Fe₂(SO₄)₃ + 3Ba(OH)₂ →2Fe(OH)₃ + 3BaSO₄

$12,$ 3Ca(OH)₂ + 2H₃PO₄ → Ca₃(PO₄)₂ + 6H₂O

$13,$ 3AgNO₃ + AlCl₃ →3AgCl + Al(NO₃)₃

$14,$ 2Fe(OH)₃ → Fe₂O₃ + 3H₂O

$15,$ C₄H₈ + 6O₂ → 4CO₂ + 4H₂O

$16,$ 2C₃H₈O + 9O₂ → 6CO₂ + 8H₂O

$17,$ FeO + CO → Fe + CO₂

$Chúc$ $bn$ $hk$ $tốt$ $!!$ $:))))$

$Xin$ $ctlhn$ $ạ.$

Em tham khảo!

***Câu 4-8 đã làm ở link: https://hoidap247.com/cau-hoi/3256495

$\text{9) 2Al(OH)3+3H2SO4$\rightarrow$Al2(SO4)3+6H2O}$

Tỉ lệ: $\text{2:3:1:6}$

$\text{10) Fe2(SO4)3+3Ba(OH)2$\rightarrow$2Fe(OH)3+3BaSO4}$

 Tỉ lệ: $\text{1:3:2:3}$

$\text{11) Na2SO4+BaCl2$\rightarrow$2NaCl+BaSO4↓}$

Tỉ lệ: $\text{1:1:2:1}$

$\text{12) 3Ca(OH)2+2H3PO4$\rightarrow$Ca3(PO4)2+6H2O}$

Tỉ lệ: $\text{3:2:1:6}$

$\text{13) AlCl3+3AgNO3$\rightarrow$3AgCl+Al(NO3)3}$

Tỉ lệ: $\text{1:3:3:1}$

$\text{14) 2Fe(OH)3$\xrightarrow{t^o}$Fe2O3+3H2O}$

Tỉ lệ: $\text{2:1;3}$

$\text{15) C4H8+6O2$\xrightarrow{t^o}$4CO2+4H2O}$

Tỉ lệ: $\text{1:6:4:4}$

$\text{16) C3H8O+4O2$\xrightarrow{t^o}$3CO2+4H2O}$

Tỉ lệ: $\text{1:4:3:4}$