Bài 1 :

a) $M_{CaSO3}$  = 40+32+16*3 = 120 (g/mol)

b) $M_{Ca(OH)2}$  = 40+(1+16)*2 = 74 (g/mol)

c) $M_{H2SO4}$  = 2*1+32+16*4 = 98  (g/mol)

d) $M_{Mg(NO3)2}$  = 24+(14+16*3)*2 = 148 (g/mol)

Bài 2 :

a) $n_{HNO3}$  = $\frac{1.26}{63}$ = 0.02 (mol)

b) $n_{Al(OH)3}$  = $\frac{3.9}{78}$ = 0.05 (mol)

c) $n_{O2}$  =  $\frac{2.479}{22.4}$  = 0.11 (mol)

d) $n_{H2S}$  = $\frac{3.7185}{22.4}$  = 0.17 (mol)

Bài 3 : 

a) $m_{Mg(OH)2}$  = 0.02*58 = 1.16 (g)

b) $m_{H2SO4}$  = 0.15*98 = 14.7 (g)

c) $V_{H2}$ = 0.05*22.4 = 1.12 (l)

d) $V_{NH3}$ = 0.03*22.4 = 0.672 (l)

Bài 4 : 

a) $dN_{2}$/$H_{2}$ = $\frac{28}{2}$ = 14

=> $N_{2}$ nặng hơn $H_{2}$  14 lần

b) $dNH_{3}$/kk = $\frac{17}{29}$ = 0.59 

=> $NH_{3}$ nhẹ hơn kk 0.59 lần

#nhi1812