Em tham khảo nha :

\(\begin{array}{l}
1)\\
a)\\
{n_{{O_2}}} = \dfrac{{3,7185}}{{24,79}} = 0,15mol\\
{m_{{O_2}}} = 0,15 \times 32 = 4,8g\\
{N_{{O_2}}} = 0,15 \times 6 \times {10^{23}} = 0,9 \times {10^{23}}\text{(Phân tử)}\\
b)\\
{n_{S{O_2}}} = \dfrac{{2,232}}{{24,79}} = 0,09mol\\
{m_{S{O_2}}} = 0,09 \times 64 = 5,76g\\
{N_{S{O_2}}} = 0,09 \times 6 \times {10^{23}} = 5,4 \times {10^{22}}\text{(Phân tử)}\\
2)\\
{n_{C{O_2}}} = \frac{{0,06 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 0,01mol\\
{m_{C{O_2}}} = 0,01 \times 44 = 0,44g\\
{V_{C{O_2}}} = 0,01 \times 24,79 = 0,2479l\\
3)\\
{n_{S{O_3}}} = \dfrac{{16}}{{80}} = 0,2mol\\
{N_{S{O_3}}} = 0,2 \times 6 \times {10^{23}} = 1,2 \times {10^{23}}\text{(Phân tử)}
\end{array}\)