ĐKXĐ : ` x ≤ 0 `

     $\sqrt{ x² - 2x }$ = $\sqrt{ 2 - 3x }$

⇔ ( $\sqrt{ x² - 2x }$ ` )² = ( ` $\sqrt{ 2 - 3x }$ ` )² `

⇔ ` | x² - 2x | = | 2 - 3x | `

⇔ ` x² - 2x = 2 - 3x ` ( Vì ` x ≤ 0 ` )

⇔ ` x² - 2x + 3x - 2 = 0 `

⇔ ` x² + x - 2 = 0 `

⇔ ` ( x² - x ) + ( 2x - 2 ) = 0 `

⇔ ` x ( x - 1 ) + 2 ( x - 1 ) = 0 `

⇔ ` ( x + 2 ) ( x - 1 ) = 0`

⇔ $\left[\begin{matrix} x + 2 = 0\\ x - 1 = 0\end{matrix}\right.$

⇔ $\left[\begin{matrix} x = -2 ( thỏa mãn )\\ x = 1 ( loại )\end{matrix}\right.$

   Vậy ` x = -2 `

$\text{$\sqrt{x²-2x}$=$\sqrt{2-3x}$}$

$\text{⇔($\sqrt{x²-2x}$)²=($\sqrt{2-3x}$)²}$

$\text{⇔x²-2x=2-3x}$

$\text{⇔x²-2x+3x=2}$

$\text{⇔x²+x=2}$

$\text{⇔x²+x-2=0}$

$\text{⇔x²+2x-x-2=0}$

$\text{⇔(x²+2x)-(x+2)=0}$

$\text{⇔x(x+2)-(x+2)=0}$

$\text{⇔\(\left[ \begin{array}{l}x+2=0\\x-1=0\end{array} \right.\) }$

$\text{⇔\(\left[ \begin{array}{l}x=-2\\x=1(loại)\end{array} \right.\) }$

$\text{⇔Vậy x=-2}$