Đáp án:

\(\begin{array}{l}
11,A\\
12,D\\
13,C\\
14,C\\
15,C
\end{array}\)

Giải thích các bước giải:

11,

\(\begin{array}{l}
CaO + 2HCl \to CaC{l_2} + {H_2}O\\
CaC{{\rm{O}}_3} + 2HCl \to CaC{l_2} + C{O_2} + {H_2}O\\
{n_{HCl}} = 0,3mol\\
 \to {n_{CaC{l_2}}} = \dfrac{1}{2}{n_{HCl}} = 0,15mol\\
 \to {m_{CaC{l_2}}} = 16,65g
\end{array}\)

12, \(2NaOH + S{O_2} \to N{a_2}S{O_3} + {H_2}O\)

13,

\(\begin{array}{l}
Zn + {H_2}S{O_4} \to Zn{\rm{S}}{O_4} + {H_2}\\
F{\rm{e}} + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
2Al + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}
\end{array}\)

14,

\(\begin{array}{l}
MgO + {H_2}S{O_4} \to MgS{O_4} + {H_2}O\\
F{e_2}{O_3} + 3{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + 3{H_2}O\\
CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
{K_2}O + {H_2}S{O_4} \to {K_2}S{O_4} + {H_2}O
\end{array}\)

15,

\(\begin{array}{l}
N{a_2}S{O_3} + {H_2}S{O_4} \to N{a_2}S{O_4} + S{O_2} + {H_2}O\\
CaC{O_3} + {H_2}S{O_4} \to CaS{O_4} + C{O_2} + {H_2}O\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}
\end{array}\)