câu 1

2H₂ + O₂ → 2H₂O

2Fe + 3Cl₂ → 2FeCl₃

Cr₂O₃ + 3H₂ → 2Cr + 3H₂O

3Ba(OH)₂ + 2K₃PO₄ → Ba₃(PO₄)₂ + 6KOH

2Al + 6HCl → 2AlCl₃ + 3H2

Cr₂(SO₄)₃ + 6NaOH → 2Cr(OH)₃ + 3Na₂SO₄

(4x+y)O₂+2CxHy→yH₂O+2xCO₂

2C_xH_yO_z +4x+y− $\frac{4x+y-2z}{2}$O_{2 →} 2xCO₂ + yH₂O

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Câu 1)

$\text{a) 2H2+O2$\xrightarrow{t^o}$2H2O}$

Tỉ lệ: $\text{2:1:2}$

$\text{b) 2Fe+3Cl2$\xrightarrow{t^o}$2FeCl3}$

Tỉ lệ: $\text{2:3:2}$

$\text{c) Cr2O3+3H2$\xrightarrow{t^o}$2Cr+3H2O}$

Tỉ lệ: $\text{1:3:2:3}$

$\text{d) 6Ba(OH)2+2K3PO4$\rightarrow$6KOH+Ba3(PO4)2↓}$

Tỉ lệ: $\text{6:2:6:1}$

$\text{e) 2Al+6HCl$\rightarrow$2AlCl3+3H2}$

Tỉ lệ: $\text{2:6:2:3}$

$\text{g) Cr2(SO4)3+6NaOH$\rightarrow$2Cr(OH)3+3Na2SO4}$

Tỉ lệ: $\text{1:6:2:3}$

$\text{h) 1CxYy+(4x+y)O2$\xrightarrow{t^o}$2xCO2+yH2O}$

Tỉ lệ: $\text{1:(4x+y):2x:y}$

$\text{i) CxHyOz+(x+$\dfrac{y}{4}$-$\dfrac{z}{2}$)O2$\xrightarrow{t^o}$xCO2+$\dfrac{y}{2}$H2O}$

Tỉ lệ: $\text{1:(x+$\dfrac{y}{4}$-$\dfrac{z}{2}$):x:$\dfrac{y}{2}$}$