Đáp án: X là Cl2
 y là Fe(OH)₃ 

 

Giải thích các bước giải:

y : Fe(OH)₃ + 3NaCl = FeCl₃ + 3NaOH
x: 4HCl+MnO₂→Cl₂+2H₂O+MnCl₂
  3Cl₂+6KOH→3H₂O+5KCl+KClO_{3
    16HCl+2KMnO4→5Cl2+8H2O+2KCl+2MnCl2}

a, 

X: $Cl_2$

$MnO_2+4HCl\to MnCl_2+Cl_2+2H_2O$

$3Cl_2+6KOH\buildrel{{t^o}}\over\to 5KCl+KClO_3+3H_2O$

$KClO_3+6HCl\to KCl+3Cl_2+3H_2O$

$KCl+H_2SO_4\buildrel{{t^o}}\over\to KHSO_4+HCl$

$MnO_2+4HCl\to MnCl_2+Cl_2+2H_2O$

$Cl_2+2NaOH\to NaCl+NaClO+H_2O$

b,

X: $Cl_2$

Y: $NaCl$ 

$2KMnO_4+16HCl\to 2KCl+2MnCl_2+5Cl_2+8H_2O$

$Cl_2+H_2O\rightleftharpoons HCl+HClO$

$Fe+2HCl\to FeCl_2+H_2$

$2FeCl_2+Cl_2\to 2FeCl_3$

$FeCl_3+3NaOH\to Fe(OH)_3+3NaCl$

$Fe(OH)_3+3HCl\to FeCl_3+3NaCl$

$FeCl_3+3NaOH\to Fe(OH)_3+3NaCl$

$2NaCl+2H_2O\buildrel{{đpmn}}\over\to 2NaOH+H_2+Cl_2$

$2NaOH+Cl_2\to NaCl+NaClO+H_2O$