a)

$dA/_H{2}$= 32 => $M_{A}$ = 32*2 = 64 (g/mol)

$n_{A}$=$\frac{8}{64}$ = 0.125 (mol)

=>$V_{A}$ = 0.125*22.4 = 2.8 (l)

b)

$dB/_O{2}$= 1.0625 => $M_{B}$ = 1.0625*32= 34 (g/mol)

$n_{B}$= $\frac{15.3}{34}$ = 0.45 (mol)

=> $V_{B}$ = 0.45*22.4 = 10.08 (l)

c)

$dC/SO_{2}$ = 1.4375 => $M_{C}$ = 1.4375*64 = 92 (g/mol)

$n_{C}$ = $\frac{165.6}{92}$ = 1.8 (mol)

=> $V_{C}$ = 1.8*22.4 = 40.32 (l)

d)

$dD/_{CO}$ = 1.5 => $M_{D}$ = 1.5*28 = 42 (g/mol)

$n_{D}$ = $\frac{57.12}{42}$ = 1.36 (mol)

=> $V_{D}$ = 1.36*22.4 = 30.464 (l)

e)

$dE/N_{2}O$ = 0.386 => $M_{E}$ = 0.386*44 = 16.984 (g/mol)

$n_{E}$ = $\frac{6.12}{16.984}$ = 0.36 (mol)

=> $V_{E}$ = 0.36*22.4 = 8.064 (l)

f)

$dF/N_{2}$ = 2.536 => $M_{F}$ = 2.536*28 = 71.008 (g/mol)

$n_{F}$ = $\frac{59.64}{71.008}$ = 0.84 (mol)

=> $V_{F}$ = 0.84*22.4 = 18.816 (l)

#nhi1812