Đáp án:

 

Giải thích các bước giải:

CuO+2HCl→CuCl2+H2O

2Al+6HCl→2AlCl3+3H2

Fe+2HCl→FeCl2+H2

Fe2O3+6HCl→2FeCl3+3H2O

FeO+2HCl→FeCl2+H2O

Fe3O4+8HCl→FeCl2+2FeCl3+4H2O

NaOH+HCl→NaCl+H2O

NaHCO3+HCl→NaCl+H2O+CO2

Na2CO3+2HCl→2NaCl+H2O+CO2

Cu+HCl→không phản ứng

KNO3+HCl→không phản ứng

MnO2+4HCl→MnCl2+2H2O+Cl2

2KMnO4+16HCl→2KCl+2MnCl2+8H2O+5Cl2

AgNO3+HCl→AgCl+HNO3

Ag+HCl→ không phản ứng

Mg+2HCl→MgCl2+H2

Zn+2HCl→ZnCl2+H2

FeCl3+HCl→không phản ứng

Cu(OH)2+2HCl→CuCl2+2H2O

Ba(OH)2+2HCl→BaCl2+2H2O

CHÚC BN HC TỐT NHÉ :33333

#Heinz Guderian

Em tham khảo nha:

\(\begin{array}{l}
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
2Al + 6HCl \to 2AlC{l_3} + 3{H_2}O\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
F{e_2}{O_3} + 6HCl \to 2FeC{l_3} + 3{H_2}O\\
FeO + 2HCl \to FeC{l_2} + {H_2}O\\
F{e_3}{O_4} + 8HCl \to 2FeC{l_3} + FeC{l_2} + 4{H_2}O\\
NaOH + HCl \to NaCl + {H_2}O\\
NaHC{O_3} + HCl \to NaCl + C{O_2} + {H_2}O\\
N{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O\\
Mn{O_2} + 4HCl \to MnC{l_2} + C{l_2} + 2{H_2}O\\
2KMn{O_4} + 16HCl \to 2KCl + 2MnC{l_2} + 5C{l_2} + 8{H_2}O\\
AgN{O_3} + HCl \to AgCl + HN{O_3}\\
Mg + 2HCl \to MgC{l_2} + {H_2}\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
Cu{(OH)_2} + 2HCl \to CuC{l_2} + 2{H_2}O\\
Ba{(OH)_2} + 2HCl \to BaC{l_2} + 2{H_2}O
\end{array}\)