Đáp án:

 25% và 75%

Giải thích các bước giải:

\(\begin{array}{l}
Mhh = 1,53125 \times 16 = 24,5\\
M{H_2} = 2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,7,5\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \searrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \nearrow \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Mhh = 24,5\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \nearrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \searrow \\
M{O_2} = 32\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,22,5\\
\frac{{n{H_2}}}{{n{O_2}}} = \frac{{7,5}}{{22,5}} = \frac{1}{3}\\
\% {H_2} = \frac{1}{4} \times 100\%  = 25\% \\
\% {O_2} = 100 - 25 = 75\% 
\end{array}\)

Đáp án:

$d_{X/CH_4}=1,53125\to \overline{M_X}=1,53125\times 16=24,5(g/mol)$

O2: 32                                         22,5 $→$ 3

                         24,5

H2: 2                                             7,5 $→$ 1

$\to \%V_{H_2}=\dfrac 14\times 100\%=25\%$

$→\%V_{O_2}=100\%-25\%=75\%$