Em tham khảo nha:

\(\begin{array}{l}
1)\\
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
CuC{l_2} + 2NaOH \to Cu{(OH)_2} + 2NaCl\\
Cu{(OH)_2} + {H_2}S{O_4} \to CuS{O_4} + 2{H_2}O\\
CuS{O_4} + BaC{l_2} \to CuC{l_2} + BaS{O_4}\\
2)\\
a)\\
Ca{(OH)_2} + C{O_2} \to CaC{O_3} + {H_2}O\\
b)\\
{n_{C{O_2}}} = \dfrac{{2,24}}{{22,4}} = 0,1\,mol\\
{n_{Ca{{(OH)}_2}}} = {n_{C{O_2}}} = 0,1\,mol\\
{C_M}Ca{(OH)_2} = \dfrac{{0,1}}{{0,2}} = 0,5M\\
c)\\
{n_{CaC{O_3}}} = {n_{C{O_2}}} = 0,1\,mol\\
{m_{CaC{O_3}}} = 0,1 \times 100 = 10g\\
d)\\
CaC{O_3} \xrightarrow{t^0} CaO + C{O_2}\\
{n_{CaO}} = {n_{CaC{O_3}}} = 0,1\,mol\\
H = 80\%  \Rightarrow {m_{CaO}} = 0,1 \times 56 \times 80\%  = 4,48g
\end{array}\)