Em tham khảo nha :

\(\begin{array}{l}
1)\\
{n_{F{e_2}{O_3}}} = \frac{8}{{160}} = 0,05mol\\
{n_{Fe}} = 2{n_{F{e_2}{O_3}}} = 0,1mol\\
{n_O} = 3{n_{F{e_2}{O_3}}} = 0,15mol\\
2)\\
{n_{S{O_2}}} = \dfrac{{5,6}}{{22,4}} = 0,2mol\\
3)\\
{n_{MgO}} = \dfrac{{9 \times {{10}^{24}}}}{{6 \times {{10}^{23}}}} = 15mol\\
4)\\
{N_{Fe}} = 0,05 \times 6 \times {10^{23}} = 3 \times {10^{22}}\text{(Nguyên tử)}\\
5)\\
{m_{{H_2}O}} = 0,2 \times 18 = 3,6g\\
6)\\
{n_{C{O_2}}} = \frac{{3,36}}{{22,4}} = 0,15mol\\
{m_{C{O_2}}} = 0,15 \times 44 = 6,6g\\
7)\\
{n_{N{H_3}}} = \dfrac{{3,4}}{{17}} = 0,2mol\\
{V_{N{H_3}}} = 0,2 \times 22,4 = 4,48l\\
8)\\
{n_{C{O_2}}} = \dfrac{{8,8}}{{44}} = 0,2mol\\
{n_{C{H_4}}} = \dfrac{{32}}{{16}} = 2mol\\
{n_{hh}} = 0,2 + 2 = 2,2mol\\
{V_{hh}} = 2,2 \times 22,4 = 49,28l\\
9)\\
{n_{{O_2}}} = \dfrac{{3,36}}{{22,4}} = 0,15mol\\
{n_{{N_2}}} = \dfrac{{4,48}}{{22,4}} = 0,2mol\\
{m_{hh}} = 0,15 \times 32 + 0,2 \times 28 = 9g\\
10)\\
{M_A} = 2,5{M_{{O_2}}} = 2,5 \times 32 = 80dvC
\end{array}\)