Câu 16:

$n_{Zn}=\dfrac{13}{65}=0,2(mol)\\ a,PTHH:Zn+2HCl\to ZnCl_2+H_2\\ b,n_{HCl}=2n_{Zn}=0,4(mol)\\ \Rightarrow m_{HCl}=0,4.36,5=14,6(g)\\ c,n_{ZnCl_2}=n_{H_2}=n_{Zn}=0,2(mol)\\ \Rightarrow m_{ZnCl_2}=0,2.136=27,2(g)\\ d,V_{H_2}=0,2.22,4=4,48(l)$

Câu 17:

$a,Fe+2HCl\to FeCl_2+H_2\\ b,4Al+3O_2\xrightarrow{t^o}2Al_2O_3\\ c,2Fe(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O\\ d,CuCl_2+2NaOH\to Cu(OH)_2\downarrow+2NaCl$

Câu 18:

$M_X=40.M_{H_2}=40.2=80(g/mol)$

Trong 1 mol khí X: $\begin{cases} n_S=\dfrac{80.40\%}{32}=1(mol)\\ n_O=\dfrac{80.60\%}{16}=3(mol) \end{cases}$

$\Rightarrow CTHH_X:SO_3$

Câu 19:

$a,PTHH:S+O_2\xrightarrow{t^o}SO_2\\ b,n_{O_2}=n_S=\dfrac{40}{32}=1,25(mol)\\ \Rightarrow V_{O_2}=1,25.22,4=28(l)$