Tìm x ∈ N biết: \(80-({4.5^2}-{3.2^3}) = {2^{10\;}} - \left( {x - 4} \right).\)

* Hướng dẫn giải

Ta có:

\(\begin{array}{*{20}{l}}
{80- \left( {{{4.5}^2}\;- {{3.2}^3}} \right) = {2^{10}}\;- \left( {x- 4} \right)}\\
{\begin{array}{*{20}{l}}
{80 - \left( {4.25 - 3.8} \right) = {2^{10}} - \left( {x - 4} \right)}\\
{80 - \left( {100 - 24} \right) = {2^{10}} - \left( {x - 4} \right)}\\
{80- 76 = {2^{10}}\;- \left( {x- 4} \right)}
\end{array}}\\
{\begin{array}{*{20}{l}}
{4 = {2^{10}}\;- \left( {x- 4} \right)}\\
{{2^{10}} - \left( {x - 4} \right) = 4}
\end{array}}\\
{x- 4 = {2^{10}}\;- 4\;}\\
{x = {2^{10}}\;- 4 + 4 = {2^{10}}\; = 1024}
\end{array}\)