A. \(25\dfrac{3}{8}\)
B. \(25\dfrac{1}{8} \)
C. \(15\dfrac{1}{8}\)
D. \(1\dfrac{1}{8}\)
B
Ta có:
\(\begin{array}{l}A = \left( {17\dfrac{{29}}{{31}} - 3\dfrac{7}{8} + 17\dfrac{{51}}{{59}}} \right) - \left( {2\dfrac{{29}}{{31}} + 7\dfrac{{51}}{{59}} - 4} \right)\\ = 17\dfrac{{29}}{{31}} - 3\dfrac{7}{8} + 17\dfrac{{51}}{{59}} - 2\dfrac{{29}}{{31}} - 7\dfrac{{51}}{{59}} + 4\\ = \left( {17\dfrac{{29}}{{31}} - 2\dfrac{{29}}{{31}}} \right) + \left( {17\dfrac{{51}}{{59}} - 7\dfrac{{51}}{{59}}} \right) - 3\dfrac{7}{8} + 4\\ = 15 + 10 - \dfrac{{31}}{8} + 4 = \dfrac{{201}}{8} = 25\dfrac{1}{8}\end{array}\)
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