Hãy tính ​\(\left( {\dfrac{{11}}{{15}}.\dfrac{{35}}{{44}}} \right):\left( {\dfrac{1}{7}.\dfrac{4}{{13}}} \right)\)

* Hướng dẫn giải

Ta có:

\(\begin{array}{l}\left( {\dfrac{{11}}{{15}}.\dfrac{{35}}{{44}}} \right):\left( {\dfrac{1}{7}.\dfrac{4}{{13}}} \right)\\ = \dfrac{7}{{12}}:\dfrac{4}{{91}}\\ = \dfrac{7}{{12}}.\dfrac{{91}}{4}\\ = \dfrac{{637}}{{48}}\end{array}\)