Cho [M = left( { frac{1}{3} + frac{{12}}{{67}} + frac{{13}}{{41}}} right) - left( { frac{{79}}{{67}} - frac{{28}}{{41}}} right) ] và [N = frac{{38}}{{45}} - left( { frac{8}{{45}} -...

Câu hỏi :

A. M = N

A. M = N

B. N >

C. 1 >

D. M >

* Đáp án

* Hướng dẫn giải

\[M = \left( {\frac{1}{3} + \frac{{12}}{{67}} + \frac{{13}}{{41}}} \right) - \left( {\frac{{79}}{{67}} - \frac{{28}}{{41}}} \right)\]

\[M = \frac{1}{3} + \frac{{12}}{{67}} + \frac{{13}}{{41}} - \frac{{79}}{{67}} + \frac{{28}}{{41}}\]

\[M = \frac{1}{3} + \left( {\frac{{12}}{{67}} - \frac{{79}}{{67}}} \right) + \left( {\frac{{13}}{{41}} + \frac{{28}}{{41}}} \right)\]

\[M = \frac{1}{3} + \left( { - 1} \right) + 1\]

\[M = \frac{1}{3}\]

\[\begin{array}{*{20}{l}}{N = \frac{{38}}{{45}} - \left( {\frac{8}{{45}} - \frac{{17}}{{51}} - \frac{3}{{11}}} \right)}\\{N = \frac{{38}}{{45}} - \frac{8}{{45}} + \frac{{17}}{{51}} + \frac{3}{{11}}}\\{N = \left( {\frac{{38}}{{45}} - \frac{8}{{45}}} \right) + \frac{{17}}{{51}} + \frac{3}{{11}}}\\{N = \frac{2}{3} + \frac{1}{3} + \frac{3}{{11}}}\\{N = 1 + \frac{3}{{11}}}\\{N = \frac{{14}}{{11}}}\end{array}\]

Vì \[\frac{1}{3}

Đáp án cần chọn là: D

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