Tìm x
a) \(\frac{7}{8} + x = \frac{3}{5}\)
b)
a) \(\frac{7}{8} + x = \frac{3}{5}\)
\(x = \frac{3}{5} - \frac{7}{8}\)
\(x = \frac{{24}}{{40}} - \frac{{35}}{{40}}\)
\(x = \frac{{24 - 35}}{{40}}\)
\(x = \frac{{ - 11}}{{40}}\)
b) \(\frac{2}{3}\left( {2x - 1} \right) = \frac{{ - 4}}{{21}}\)
\[2x - 1 = \frac{{ - 4}}{{21}}:\frac{2}{3}\]
\[2x - 1 = \frac{{ - 4}}{{21}}.\frac{3}{2}\]
\[2x - 1 = \frac{{ - 2}}{7}\]
\[2x = \frac{{ - 2}}{7} + 1\]
\[2x = \frac{5}{7}\]
\[x = \frac{5}{7}:2\]
\[x = \frac{5}{7}.\frac{1}{2}\]
\[x = \frac{5}{{14}}\]
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