Tìm x a) 7/2 -2x = 5(1/3) : 8/3 b) (2x - 4/3) -1(1/3) = -8/9

* Hướng dẫn giải

a) $\frac{7}{2}-2x=5\frac{1}{3}:\frac{8}{3}$ 

$\frac{7}{2}-2x=\frac{16}{3}:\frac{8}{3}$ 

$\frac{7}{2}-2x=\frac{16}{3}.\frac{3}{8}$ 

$\frac{7}{2}-2x=2$ 

$2x=\frac{7}{2}-2$ 

$2x=\frac{7}{2}-\frac{4}{2}$ 

$2x=\frac{3}{2}$ 

$x=\frac{3}{2}:2$ 

$x=\frac{3}{2}.\frac{1}{2}$ 

$x=\frac{3}{4}$ 

b) $(2x-\frac{4}{3})-1\frac{1}{3}=\frac{-8}{9}$ 

$(2x-\frac{4}{3})-\frac{4}{3}=\frac{-8}{9}$ 

$2x-\frac{4}{3}=\frac{-8}{9}+\frac{4}{3}$ 

$2x-\frac{4}{3}=\frac{-8}{9}+\frac{12}{9}$ 

$2x-\frac{4}{3}=\frac{4}{9}$ 

$2x=\frac{4}{9}+\frac{4}{3}$ 

$2x=\frac{4}{9}+\frac{12}{9}$ 

$2x=\frac{16}{9}$ 

$x=\frac{16}{9}:2$

$x=\frac{16}{9}.\frac{1}{2}$ 

$x=\frac{8}{9}$