\(\begin{array}{l}
a,\,\,\frac{{ - 2}}{3} + \frac{1}{5} = \frac{{ - 10 + 3}}{{15}} = \frac{{ - 7}}{{15}}\\
b,\,\,3\frac{{11}}{{13}} - 5\frac{{11}}{{13}} = 3 + \frac{{11}}{{13}} - 5 - \frac{{11}}{{13}} = - 2\\
c,\,\,1\frac{2}{3}:\frac{{ - 5}}{3} = \frac{5}{3}:\frac{{ - 5}}{3} = \frac{5}{3}.\frac{{ - 3}}{5} = - 1\\
d,\,\,\frac{{31}}{{17}} + \frac{{ - 5}}{{13}} + \frac{{ - 8}}{{13}} - \frac{{14}}{{17}} = \left( {\frac{{31}}{{17}} - \frac{{14}}{{17}}} \right) + \left( {\frac{{ - 5}}{{13}} + \frac{{ - 8}}{{13}}} \right) = 1 + \left( { - 1} \right) = 0
\end{array}\)
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