Thực hiện phép tính (tính hợp lý nếu có thể): a) \(\frac{4}{{11}}.\frac{{ - 2}}{7} + \frac{4}{{11}}.

* Hướng dẫn giải

a) Ta có: \(\frac{4}{{11}}.\frac{{ - 2}}{7} + \frac{4}{{11}}.\frac{{ - 4}}{7} + \frac{4}{{11}}.\frac{{ - 1}}{7}\)

\(\begin{array}{l}
 = \frac{4}{{11}}.\left( {\frac{{ - 2}}{7} + \frac{{ - 4}}{7} + \frac{{ - 1}}{7}} \right)\\
 = \frac{4}{{11}}.\left( {\frac{{ - 2}}{7} - \frac{4}{7} - \frac{1}{7}} \right)\\
 = \frac{4}{{11}}.\left( {\frac{{ - 7}}{7}} \right)\\
 = \frac{4}{{11}}.\left( { - 1} \right)\\
 = \frac{{ - 4}}{{11}}
\end{array}\)

b) \(50\%  + 1,5:\left( {{{2018}^0} - \frac{2}{3}} \right)\)

\(\begin{array}{l}
 = \frac{1}{2} + \frac{3}{2}:\left( {1 - \frac{2}{3}} \right)\\
 = \frac{1}{2} + \frac{3}{2}:\left( {\frac{3}{3} - \frac{2}{3}} \right)\\
 = \frac{1}{2} + \frac{3}{2}:\frac{1}{3}\\
 = \frac{1}{2} + \frac{3}{2}.\frac{3}{1}\\
 = \frac{1}{2} + \frac{9}{2}\\
 = \frac{{10}}{2}\\
 = 5
\end{array}\)