Tìm x biết: \(\left| {\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \frac{{\rm{1}}}{{\rm{2}}}} \right| - \frac{{\rm{1}}}{{\rm{2}}} = \frac{{\rm{1}}}{{\rm{4}}
Câu hỏi :
Tìm x biết: \(\left| {\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \frac{{\rm{1}}}{{\rm{2}}}} \right| - \frac{{\rm{1}}}{{\rm{2}}} = \frac{{\rm{1}}}{{\rm{4}}}\)
* Đáp án
* Hướng dẫn giải
\(\left| {\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \frac{{\rm{1}}}{{\rm{2}}}} \right| - \frac{{\rm{1}}}{{\rm{2}}} = \frac{{\rm{1}}}{{\rm{4}}}\)
\(\left| {\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \frac{{\rm{1}}}{{\rm{2}}}} \right| = \frac{{\rm{1}}}{{\rm{4}}} + \frac{{\rm{1}}}{{\rm{2}}}\)
\(\left| {\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \frac{{\rm{1}}}{{\rm{2}}}} \right| = \frac{{\rm{1}}}{{\rm{4}}} + \frac{{\rm{2}}}{{\rm{4}}}\)
\(\left| {\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \frac{{\rm{1}}}{{\rm{2}}}} \right| = \frac{{\rm{3}}}{{\rm{4}}}\)
\(\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \frac{{\rm{1}}}{{\rm{2}}} = \frac{{\rm{3}}}{{\rm{4}}}\) hoặc \(\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \frac{{\rm{1}}}{{\rm{2}}} = \frac{{ - {\rm{3}}}}{{\rm{4}}}\)
\(\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \frac{{\rm{3}}}{{\rm{4}}} + \frac{{\rm{1}}}{{\rm{2}}}\) hoặc \(\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \frac{{ - {\rm{3}}}}{{\rm{4}}} + \frac{{\rm{1}}}{{\rm{2}}}\)
\(\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \frac{{\rm{5}}}{{\rm{4}}}\) hoặc \(\frac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \frac{{ - {\rm{1}}}}{{\rm{4}}}\)
\({\rm{x}} = \frac{{\rm{5}}}{{\rm{4}}}{\rm{:}}\frac{{\rm{3}}}{{\rm{4}}}\) hoặc \({\rm{x}} = \frac{{ - {\rm{1}}}}{{\rm{4}}}{\rm{:}}\frac{{\rm{3}}}{{\rm{4}}}\)
\({\rm{x}} = \frac{{\rm{5}}}{{\rm{3}}}\) hoặc \({\rm{x}} = \frac{{ - {\rm{1}}}}{{\rm{3}}}\)
Câu hỏi trên thuộc đề trắc nghiệm dưới đây !
Đề thi HK2 môn Toán 6 Phòng GD & ĐT Quận 1 năm học 2017 - 2018
Copyright © 2021 HOCTAP247