a) \(\begin{array}{l}
\left( {3x + 1} \right):\left( { - 4} \right) = - 28\\
\Rightarrow 3x + 1 = - 28:( - 4)\\
\Rightarrow 3x + 1 = 7\\
\Rightarrow 3x = 7 - 1 = 6\\
\Rightarrow x = 6:3 = 2
\end{array}\)
Vậy x = 2
b) Ta có
\(\begin{array}{l}
x - \frac{4}{9} = \frac{5}{{18}}\\
\Rightarrow x = \frac{4}{9} + \frac{5}{{18}} \Rightarrow x = \frac{8}{{18}} + \frac{5}{{18}}\\
\Rightarrow x = \frac{{13}}{{18}}
\end{array}\)
Vậy \9x = \frac{{13}}{{18}}\)
c)
\(\begin{array}{l}
\frac{2}{3}x - \frac{3}{4}x = - 1\frac{1}{6} \Rightarrow x\left( {\frac{2}{3} - \frac{3}{4}} \right) = - \frac{7}{6} \Rightarrow x\left( {\frac{8}{{12}} - \frac{9}{{12}}} \right) = - \frac{7}{6}\\
\Rightarrow x\left( {\frac{{ - 1}}{{12}}} \right) = - \frac{7}{6}\\
\Rightarrow x = - \frac{7}{6}:\left( {\frac{{ - 1}}{{12}}} \right) = - \frac{7}{6}.\left( { - 12} \right) = 14
\end{array}\)
Vậy x = 14
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