Tìm x thuộc Z, biết: -7/8+5/6

* Hướng dẫn giải

$\frac{-7}{8}+\frac{5}{6}<\frac{x}{24}\le \frac{5}{8}+\frac{-5}{12}$

$$\begin{gathered} \iff \frac{-21}{24}+\frac{20}{24}\le \frac{x}{24}\le \frac{15}{24}+\frac{-10}{24} \\ \iff \frac{-1}{24}\le \frac{x}{24}\le \frac{5}{24} \end{gathered}$$

-1 ≤ x ≤ 5 mà x ∈ Z. Do đó: x ∈ { -1 ; 0 ; 1 ; 2 ; 3 ; 4 ; 5 }