Tìm x, biết: |x|-3/4=5/3

* Hướng dẫn giải

$a\left)\right|x|-\frac{3}{4}=\frac{5}{3}=>|x|=\frac{29}{12}$$=>\left[\begin{array}{l}x=\frac{29}{12}\\ x=\frac{-29}{12}\end{array}\right.$

b) $\left|x-\frac{3}{2}\right|=1=>\left[\begin{array}{l}x-\frac{3}{2}=1\\ x-\frac{3}{2}=-1\end{array}\right.=>\left[\begin{array}{l}x=\frac{5}{2}\\ x=\frac{1}{2}\end{array}\right.$

c) $\left|x-\frac{3}{2}\right|+\frac{11}{4}=\frac{15}{4}=>\left|x-\frac{3}{2}\right|=1=>\left[\begin{array}{l}x=\frac{5}{2}\\ x=\frac{1}{2}\end{array}\right.$

d) $\frac{17}{4}-\left|\frac{5}{6}-x\right|=-\frac{7}{4}=>\left|\frac{5}{6}-x\right|=6=>\left[\begin{array}{l}x=\frac{-31}{6}\\ x=\frac{41}{6}\end{array}\right.$

e)

 $$\begin{gathered} {\left(x+\frac{1}{5}\right)}^2-\frac{9}{25}=0=>{\left(x+\frac{1}{5}\right)}^2=\frac{9}{25} \\ =>\left[\begin{array}{l}x+\frac{1}{5}=\frac{3}{5}\\ x+\frac{1}{5}=\frac{-3}{5}\end{array}\right.=>\left[\begin{array}{l}x=\frac{2}{5}\\ x=\frac{-4}{5}\end{array}\right. \end{gathered}$$

f) ${\left(x+\frac{1}{5}\right)}^2+\frac{17}{25}=\frac{26}{25}=>{\left(x+\frac{1}{5}\right)}^2=\frac{9}{25}=>\left[\begin{array}{l}x=\frac{2}{5}\\ x=\frac{-4}{5}\end{array}\right.$