Thực hiện phép tính: a, A = 3 mũ 2 nhân 5 mũ 2 nhân 4 mũ 3

* Hướng dẫn giải

a, A = $\left[\left(3^2.5^2.4^3\right):\left(2^3.3^2\right)\right].{2005}^0$

= $\left[\left(3^2.5^2.2^6\right):\left(2^3.3^2\right)\right].1$

= $\left[3.5^2.2^3\right]$ = 3.25.8 = 600

b, B = 194.12+6.437.2+3.369.4

= 194.12+437.12+369.12

= 12.(194+437+369)

= 12.1000 = 12000

c, C = $\left(5^{16}+{16}^5\right)\left(3^{17}-3^{10}\right)\left(2^4-4^2\right)$

= $\left(5^{16}+{16}^5\right)\left(3^{17}-3^{10}\right)\left(4^2-4^2\right)$

= $\left(5^{16}+{16}^5\right)\left(3^{17}-3^{10}\right).0$ = 0

d, D = $\left(5^{2007}-5^{2006}\right):\left(5^{2005}.5\right)$

= $\left(5^{2007}-5^{2006}\right):5^{2006}$

= $5^{2006}.\left(5-1\right):5^{2006}$ = 4