Tìm x, biết: a) |x-2| = |-3/5| + 2/3 b) |x-4/3| = 1/6 + |5/3 -1/2| + 7/12

* Hướng dẫn giải

a) $\left|x-2\right|=\left|\frac{-3}{5}\right|+\frac{2}{3}\iff \left|x-2\right|=\frac{19}{15}$$\iff \left[\begin{array}{l}x-2=\frac{19}{15}\\ x-2=\frac{-19}{15}\end{array}\right.\iff \left[\begin{array}{l}x=\frac{49}{15}\\ x=\frac{11}{15}\end{array}\right.$

b) $\left|x-\frac{4}{3}\right|=\frac{1}{6}+\left|\frac{5}{3}-\frac{1}{2}\right|+\frac{7}{12}\iff \left|x-\frac{4}{3}\right|=\frac{23}{12}$$\iff \left[\begin{array}{l}x-\frac{4}{3}=\frac{23}{12}\\ x-\frac{4}{3}=\frac{-23}{12}\end{array}\right.\iff \left[\begin{array}{l}x=\frac{13}{4}\\ x=\frac{-7}{12}\end{array}\right.$