Cho B = 12/(2.4)^2 + 20/(4.6)^2 + ... + 388/(96.98)^2 + 396/(98.100)^2

Câu hỏi :

Cho $B=\frac{12}{{\left(2.4\right)}^2}+\frac{20}{{\left(4.6\right)}^2}+\mathrm{...}+\frac{388}{{\left(96.98\right)}^2}+\frac{396}{{\left(98.100\right)}^2}$. Hãy so sánh B với $\frac{1}{4}$