Tính đạo hàm của hàm số y= (2x^2 + x - 1) ^ 2/ 3 y' = 2 (4x +1) / 3

A. $y^{\text{'}}=\frac{2\left(4\text{x}+1\right)}{3\sqrt[3]{2{\text{x}}^2+x-1}}$

B. $y^{\text{'}}=\frac{2\left(4\text{x}+1\right)}{3\sqrt[3]{{\left(2{\text{x}}^2+x-1\right)}^2}}$

C. $y^{\text{'}}=\frac{3\left(4\text{x}+1\right)}{2\sqrt[3]{2{\text{x}}^2+x-1}}$

D. $y^{\text{'}}=\frac{3\left(4\text{x}+1\right)}{2\sqrt[3]{{\left(2{\text{x}}^2+x-1\right)}^2}}$