Tìm giao tuyến của hai mặt phẳng (P): x-2y+z-3=0 và (Q): x-3y+z-4=0

A. $\mathrm{d}:\left\{\begin{array}{l}\mathrm{x}=-\mathrm{t}\\ \mathrm{y}=-1\\ \mathrm{z}=1-\mathrm{t}\end{array}\right.$

B. $\mathrm{d}:\left\{\begin{array}{l}\mathrm{x}=\mathrm{t}\\ \mathrm{y}=-1\\ \mathrm{z}=1-\mathrm{t}\end{array}\right.$

C. $\mathrm{d}:\left\{\begin{array}{l}\mathrm{x}=\mathrm{t}\\ \mathrm{y}=-\mathrm{t}\\ \mathrm{z}=1-\mathrm{t}\end{array}\right.$

D. $\mathrm{d}:\left\{\begin{array}{l}\mathrm{x}=\mathrm{t}\\ \mathrm{y}=-1+\mathrm{t}\\ \mathrm{z}=1-\mathrm{t}\end{array}\right.$