Cho z1=1+ căn bậc hai 3,z2=7+i/4-3i

* Hướng dẫn giải

Đáp án B

Ta có

$\left.\begin{array}{l}{z}_1^{25}={\left(1+\sqrt{3}i\right)}^{25}=8^8+8^8\sqrt{3}i\\ z_2^{10}={\left(\frac{7+i}{4-3i}\right)}^{10}={\left(2i\right)}^5=2^{5}i\\ z_3^{2016}={\left(1-i\right)}^{2016}={\left(-2i\right)}^{1008}=2^{1008}\end{array}\right\}\Rightarrow w=z_1^{25}.z_2^{10}.z_3^{2016}=-2^{1037}\sqrt{3}+2^{1037}i.$