Tìm x biết:
Giải:
a) \( x- \dfrac{3}{4}= \dfrac{1}{2} \Rightarrow x= \dfrac{1}{2}+\dfrac{3}{4}=\dfrac{5}{4} \ vậy \ x=\dfrac{5}{4}\)
b) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3} \Leftrightarrow \dfrac{-5}{6}-x=\dfrac{1}{4} \)
\(x= \dfrac{-5}{6}-\dfrac{1}{4}=-\dfrac{13}{12}\ vậy \ x=-\dfrac{13}{12}\)
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