\(\begin{array}{l}
a)\\
C{H_3}COONa + NaOH \to N{a_2}C{O_3} + C{H_4}\\
2C{H_4} \to {C_2}{H_2} + 3{H_2}\\
{C_2}{H_2} + HCl \to C{H_2} = CHCl\\
nC{H_2} = CHCl \to {( - C{H_2} - CHCl - )_n}
\end{array}\)

 b)

\(\begin{array}{l}
CaC{O_3} \to CaO + C{O_2}\\
CaO + 3C \to Ca{C_2} + CO\\
Ca{C_2} + 2{H_2}O \to Ca{(OH)_2} + {C_2}{H_2}\\
2CH \equiv CH \to C{H_2} = CH - C \equiv CH\\
C{H_2} = CH - C \equiv CH + {H_2} \to C{H_2} = CH - CH = C{H_2}\\
nC{H_2} = CH - CH = C{H_2} \to {( - C{H_2} - CH = CH - C{H_2})_n}
\end{array}\)

\(\begin{array}{l}
c)\\
{C_3}{H_8} \to C{H_4} + {C_2}{H_4}\\
2C{H_4} \to {C_2}{H_2} + 3{H_2}\\
3{C_2}{H_2} \to {C_6}{H_6}\\
{C_2}{H_2} + {H_2} \to {C_2}{H_4}\\
{C_2}{H_4} + {H_2}O \to {C_2}{H_5}OH\\
{C_2}{H_5}OH \to {C_2}{H_4} + {H_2}O
\end{array}\)

Đáp án:

 

Giải thích các bước giải:

a.

CH3COONa + NaOH --to,CaO--> Na2CO3 + CH4

2CH4 --to,làm lạnh nhanh--> C2H2 + 3H2

C2H2 + HCl → C2H3Cl

nCH2=CH-Cl --to,xt,p--> (CH2-CH(Cl)-)n

b.

(1)C3H8 --to,Ni--> CH4 + C2H4

                                  (X)        (Y)

(2) 2CH4 --to,làm lạnh nhanh--> C2H2 + 3H2

(3) 3C2H2 --to,xt,p--> C6H6

(4) C2H2 + H2 --to,Pd--> C2H4

(5) C2H4 + H2O --xt,to--> C2H5OH

(6) C2H5OH --170 độ C,xt--> C2H4 + H2O