$🎿dangducan🎿$

$a)$

$(1)$ $Fe + 3Cl_{2}$ $\overset{t^{\circ } }{\rightarrow}$ $2FeCl_{3} $

$(2)$ $FeCl_{3}$ $+$ $3NaOH$ $→$ $Fe(OH)_{3}$ $+ 3NaCl$

$(3)$ $2Fe(OH)_{3}$ $+ 3H_{2}SO_{4} →$ $Fe_{2}(SO_{4})_{3}$ $+ 6H_{2}O$

$(4)$ $Fe_{2}(SO_{4})_{3}$ $+$ $3BaCl_{2}$ $→ 3BaSO_{4}$ $+ 2FeCl_{3}$

$b)$

$(1)$ $Fe(NO_{3})_{3} + 3NaOH → Fe(OH)_{3} + 3NaNO_{3}$

$(2)$ $2Fe(OH)_{3} \overset{t^{\circ } }{\rightarrow} Fe_{2}O_{3} + 3H_{2}O$

$(3)$ $Fe_{2}O_{3} + 3CO → 2Fe + 3CO_{2}$

$(4)$ $Fe + 2HCl → FeCl_{2} + H_{2}$

$(5)$ $FeCl_{2} + 2NaOH → Fe(OH)_{2} + 2NaCl$

a) 2Fe + 3Cl2 -> 2FeCl3

FeCl3 + 3NaOH-> Fe(OH)3 + 3NaCl

2Fe(OH)3 + AL2(S04)3 -> 2Al(OH)3 + Fe2(S04)3

Fe2(S04)3 + 3BaCl2 -> 3BaS04 + 2FeCl3

b) Fe(N03)3 + 3NaOH -> Fe(OH)3 +3NaN03

2Fe(OH)3 -> Fe203 +3H20

Fe203 + 3H2 -> 2Fe + 3H20

Fe + 2HCL -> FeCl2 + H2

FeCl2 + 2NaOH -> Fe(OH)2 + 2NaCL