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Đáp án+ Giải thích các bước giải:

$\text{Đáp án+Giải thích các bước giải:}$

$\text{A.}$

$\text{CuO + $H_{2}$$\xrightarrow{t^o}$Cu + $H_{2}O$}$

$\text{FeO + $H_{2}$$\xrightarrow{t^o}$Fe + $H_{2}O$}$

$\text{$Fe_{3}O_{4}$ + $4H_{2}$$\xrightarrow{t^o}$3Fe + $4H_{2}O$}$

$\text{HgO + $H_{2}$$\xrightarrow{t^o}$Hg + $H_{2}O$}$

$\text{PbO + $H_{2}$$\xrightarrow{t^o}$Pb + $H_{2}O$}$

$\text{$2H_{2}$ + $O_{2}$$\xrightarrow{t^o}$$2H_{2}O$}$

$\text{$Fe_{2}O_{3}$ + $3H_{2}$$\xrightarrow{t^o}$2Fe + $3H_{2}O$}$

$\text{B.}$

$\text{Tác dụng với HCl:}$

$\text{Mg + 2HCl→$MgCl_{2}$ + $H_{2}$}$

$\text{2Al + 6HCl→$2AlCl_{3}$ + $3H_{2}$}$

$\text{Zn + 2HCl→$ZnCl_{2}$ + $H_{2}$}$

$\text{Fe + 2HCl→$FeCl_{2}$ + $H_{2}$}$

$\text{Ca + 2HCl→$CaCl_{2}$ + $H_{2}$}$

$\text{2Na + 2HCl→2NaCl + $H_{2}$}$

$\text{Tác dụng với $H_{2}SO_{4}$:}$

$\text{Mg + $H_{2}SO_{4}$→$MgSO_{4}$ + $H_{2}$}$

$\text{2Al + $3H_{2}SO_{4}$→$Al_{2}(SO_{4})_{3}$ + $3H_{2}$}$

$\text{Zn + $H_{2}SO_{4}$→$ZnSO_{4}$ + $H_{2}$}$

$\text{Fe + $H_{2}SO_{4}$→$FeSO_{4}$ + $H_{2}$}$

$\text{Ca + $H_{2}SO_{4}$→$CaSO_{4}$ + $H_{2}$}$

$\text{2Na + $H_{2}SO_{4}$→$Na_{2}SO_{4}$ + $H_{2}$}$

$\text{C.}$

$\text{$SO_{3}$ + $H_{2}O$→$H_{2}SO_{4}$}$

$\text{$P_{2}O_{5}$ + $3H_{2}O$→$2H_{3}PO_{4}$}$

$\text{$SO_{2}$ + $H_{2}O$→$H_{2}SO_{3}$}$

$\text{CaO + $H_{2}O$→$Ca(OH)_{2}$}$

$\text{BaO + $H_{2}O$→$Ba(OH)_{2}$}$

$\text{$Na_{2}O$ + $H_{2}O$→2NaOH}$

$\text{2K + $2H_{2}O$→2KOH + $H_{2}$}$

$\text{Ca + $2H_{2}O$→$Ca(OH)_{2}$ + $H_{2}$}$

$\text{$SiO_{2}$ + $H_{2}O$→$H_{2}SiO_{3}$}$