Đáp án:

\(\begin{array}{l}
a){m_{Cu}} = 4,48g\\
b){m_{{\rm{dd}}}} = 111,44g\\
c)C{M_{FeS{O_4}}} = 0,7M
\end{array}\)

Giải thích các bước giải:

\(\begin{array}{l}
Fe + C{\rm{uS}}{O_4} \to FeS{O_4} + Cu\\
{m_{{\rm{dd}}CuS{O_4}}} = 112g\\
 \to {m_{CuS{O_4}}} = \dfrac{{112 \times 10\% }}{{100\% }} = 11,2g\\
 \to {n_{CuS{O_4}}} = 0,07mol
\end{array}\)

\(\begin{array}{l}
a)\\
{n_{Cu}} = {n_{CuS{O_4}}} = 0,07mol\\
 \to {m_{Cu}} = 4,48g
\end{array}\)

\(\begin{array}{l}
b)\\
{n_{Fe}} = {n_{CuS{O_4}}} = 0,07mol\\
 \to {m_{Fe}} = 3,92g\\
{m_{{\rm{dd}}}} = {m_{Fe}} + {m_{{\rm{dd}}CuS{O_4}}} - {m_{Cu}} = 111,44g
\end{array}\)

\(\begin{array}{l}
c)\\
{n_{FeS{O_4}}} = {n_{CuS{O_4}}} = 0,07mol\\
 \to C{M_{FeS{O_4}}} = \dfrac{{0,07}}{{0,1}} = 0,7M
\end{array}\)