\(a)\)

\(KCl:Kali{\text{ clorua}}\)

\(NH_4^{}NO_3^{}:Amoni\;{\text{nitrat}}\)

\({\text{NH}}_4^{}Cl:Amoni{\text{ Clorua}}\)

\((NH_4^{})_2^{}SO_4^{}:Amoni{\text{ sunfat}}\)

\({\text{Ca(H}}_2^{}PO_4^{})_2^{}:canxi{\text{ dihidrophotphat}}\)

\({\text{(NH}}_4^{})_2^{}HPO_4^{}:Diamoni{\text{ hidrophotphat}}\)

\({\text{KNO}}_3^{}:Kali\;{\text{nitrat}}\)

\(b)\)

\(Phan{\text{ Kali:KCl}}\)

\({\text{Phan lan: Ca(H}}_2^{}PO_4^{})_2^{}\)

\(Phan{\text{ nito:}}NH_4^{}NO_3^{};{\text{NH}}_4^{}Cl;(NH_4^{})_2^{}SO_4^{}\)

\(Phan{\text{ bon kep:(NH}}_4^{})_2^{}HPO_4^{};{\text{KNO}}_3^{}\)

\(c)\)

\(C\% _{NH_4^{}NO_3^{}}^{} = \frac{{14.2}}{{80}}.100 = 35\% \)

\(C\% _{NH_4^{}Cl}^{} = \frac{{14}}{{53,5}}.100 = 26,16\% \)

\(C\% _{(NH_4^{})_2^{}SO_4^{}}^{} = \frac{{14.2}}{{132}}.100 = 21,21\% \)

\(C\% _{{\text{(NH}}_4^{})_2^{}HPO_4^{}}^{} = \frac{{14.2}}{{132}}.100 = 21,21\% \)

\(C\% _{{\text{KNO}}_3^{}}^{} = \frac{{14}}{{101}}.100 = 13,86\% \)