Em tham khảo nha:

\(\begin{array}{l}
1mol = 24,76l\\
a)\\
{n_{S{O_2}}} = \dfrac{{2,469}}{{24,76}} = 0,0997\,mol\\
{m_{S{O_2}}} = 0,0997 \times 64 = 6,3808g\\
b)\\
{n_{N{O_2}}} = \dfrac{{4,958}}{{24,76}} \approx 0,2\,mol\\
{m_{N{O_2}}} = 0,2 \times 46 = 9,2g\\
c)\\
{n_{C{O_2}}} = \dfrac{{7,437}}{{24,76}} = 0,332\,mol\\
{m_{C{O_2}}} = 0,332 \times 44 = 14,608g\\
d)\\
{n_{N{H_3}}} = \dfrac{{3,7185}}{{24,76}} = 0,15\,mol\\
{m_{N{H_3}}} = 0,15 \times 17 = 2,55g\\
e)\\
{n_{{H_2}S}} = \dfrac{{12,395}}{{24,76}} = 0,5\,mol\\
{m_{{H_2}S}} = 0,5 \times 34 = 17g\\
f)\\
{n_{S{O_2}}} = \dfrac{{14,874}}{{24,76}} = 0,6\,mol\\
{m_{S{O_2}}} = 0,6 \times 64 = 38,4g
\end{array}\)