Đáp án:

Giải thích các bước giải:

1) $15x-\frac{10}{x^2}+3=0\\\Leftrightarrow 15x^3+3x^2-10=0\\\Leftrightarrow x=0,8117439526$

2) $(x-\frac{1}{x}+1)-(x^2+x-\frac{2}{x}+1)=(x+\frac{1}{x}-1)-x-2\\\Leftrightarrow -x^2+\frac{1}{x}=\frac{1}{x}-3\\\Leftrightarrow -x^2+3=0\\\Leftrightarrow x^2-3=0\\\Leftrightarrow x=\pm\sqrt{3}$

Giải thích các bước giải:

1.Ta có :
$\dfrac{15x-10}{x^2+3}=0$ 
$\to 15x-10=0$

$\to x=\dfrac{10}{15}=\dfrac 23$

2.ĐKXĐ : $x\ne -1,1$ 
$\dfrac{x-1}{x+1}-\dfrac{x^2+x-2}{x-1}=\dfrac{x+1}{x-1}-x-2$

$\to \dfrac{x-1}{x+1}-\dfrac{(x+2)(x-1)}{x-1}=\dfrac{x+1}{x-1}-x-2$

$\to \dfrac{x-1}{x+1}-(x+2)=\dfrac{x+1}{x-1}-(x+2)$

$\to \dfrac{x-1}{x+1}=\dfrac{x+1}{x-1}$

$\to (x-1)^2=(x+1)^2$

$\to x^2-2x+1=x^2+2x+1$

$\to 4x=0$

$\to x=0$