A. \(x = \dfrac{2}{{15}} \)
B. \(x = \dfrac{{22}}{{15}} \)
C. không tồn tại x
D. \(x = \dfrac{{22}}{{15}}; x = \dfrac{2}{{15}}\)
D
Ta có:
\(\begin{array}{l}\left| {\dfrac{3}{4}x - \dfrac{3}{5}} \right| - \dfrac{1}{2} = 0\\\left| {\dfrac{3}{4}x - \dfrac{3}{5}} \right| = \dfrac{1}{2}\end{array}\)
\(\begin{array}{l}TH1:\dfrac{3}{4}x - \dfrac{3}{5} = \dfrac{1}{2}\\\dfrac{3}{4}x = \dfrac{{11}}{{10}}\\x = \dfrac{{22}}{{15}}\end{array}\)
\(\begin{array}{l}TH2:\dfrac{3}{4}x - \dfrac{3}{5} = \dfrac{{ - 1}}{2}\\\dfrac{3}{4}x = \dfrac{1}{{10}}\\x = \dfrac{2}{{15}}\end{array}\)
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