Tìm số nguyên x biết \(\frac{5}{6} + \frac{{ - 7}}{8} \le \frac{x}{{24}} \le \frac{{ - 5}}{{12}} + \frac{5}{8}\)

* Hướng dẫn giải

\(\begin{array}{l}
\frac{5}{6} + \frac{{ - 7}}{8} \le \frac{x}{{24}} \le \frac{{ - 5}}{{12}} + \frac{5}{8}\\
\frac{{ - 1}}{{24}} \le \frac{x}{{24}} \le \frac{5}{{24}}\\
x \in \left\{ { - 1;0;1;2;3;4;5} \right\}
\end{array}\)