A. \(A = \left\{ {6;\,\,10;\,\,14;\,\,18;\,\,22;\,\,26;\,\,30;\,\,34;\,\,38;\,\,42} \right\} = \left\{ {x \in \mathbb{N}|\,\,x = 4k + 2,\,\,1 \le k \le 10} \right\}.\)
B. \(A = \left\{ {6;\,\,10;\,\,14;\,\,18;\,\,20;\,\,24;\,\,28;\,\,32;\,\,36;\,\,40} \right\} = \left\{ {x \in \mathbb{N}|\,\,x = 4k,\,\,1 \le k \le 10} \right\}.\)
C. \(A = \left\{ {6;\,\,10;\,\,14;\,\,18;\,\,22;\,\,26;\,\,30;\,\,34;\,\,38;\,\,42} \right\} = \left\{ {x \in \mathbb{N}|\,\,x = 2k + 4,\,\,1 \le k \le 10} \right\}.\)
D. \(A = \left\{ {6;\,\,10;\,\,14;\,\,20;\,\,26;\,\,28;\,\,32;\,\,38;\,\,40;\,\,46} \right\} = \left\{ {x \in \mathbb{N}|\,\,x = 2k + 2,\,\,1 \le k \le 10} \right\}.\)
A
Ta có: \(6 = 4.1 + 2\)
\(\begin{array}{l}10 = 4.2 + 2\\14 = 4.3 + 2\\18 = 4.4 + 2\end{array}\)
Như vậy ta có tập hợp \(A = \left\{ {6;\,\,10;\,\,14;\,\,18;\,\,22;\,\,26;\,\,30;\,\,34;\,\,38;\,\,42} \right\} = \left\{ {x \in \mathbb{N}|\,\,x = 4k + 2,\,\,1 \le k \le 10} \right\}.\)
Chọn A.
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