A. \(S = \frac{{204}}{{673}}\)
B. \(S = \frac{{224}}{{673}}\)
C. \(S = \frac{{224}}{{763}}\)
D. \(S = \frac{{242}}{{673}}\)
B
Ta có:
\(\begin{array}{l}S = \frac{2}{{3.5}} + \frac{2}{{5.7}} + \frac{2}{{7.9}} + ... + \frac{2}{{2017.2019}}\\\,\,\,\, = \frac{1}{3} - \frac{1}{5} + \frac{1}{5} - \frac{1}{7} + \frac{1}{7} - \frac{1}{9} + ... + \frac{1}{{2017}} - \frac{1}{{2019}}\\\,\,\,\, = \frac{1}{3} - \frac{1}{{2019}}\\\,\,\,\, = \frac{{672}}{{2019}} = \frac{{224}}{{673}}\end{array}\)
Vậy \(S = \frac{{224}}{{673}}\)
Chọn B
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